1. ## equations

Hi,

Im trying a different question on the same topic as my orignal thread but Im still not sure how to find:-

$
C_R
$

When:-

$
2-C_R^2=2-2.6C_R+1.8C_R^2
$

Cheers,

Ben

2. Looks like it works the same way as the other one you posted:

$2-C_R^2=2--2.6C_R+1.8C_R^2$

Subtract 2 from each side; then, add $C_R^2$ to both sides.

$0=-2.6C_R+2.8C_R^2$

$2.8C_R^2-2.6C_R=0$

Factor out a $2C_R$

$2C_R(1.4C_R-1.3)=0$

$2C_R=0 \ or \ 1.4C_R=1.3$

Working with the latter equation:

$C_R=\frac{1.3}{1.4}= \frac{13}{14}$