Hi,
Im trying a different question on the same topic as my orignal thread but Im still not sure how to find:-
$\displaystyle
C_R
$
When:-
$\displaystyle
2-C_R^2=2-2.6C_R+1.8C_R^2
$
Cheers,
Ben
Looks like it works the same way as the other one you posted:
$\displaystyle 2-C_R^2=2--2.6C_R+1.8C_R^2$
Subtract 2 from each side; then, add $\displaystyle C_R^2$ to both sides.
$\displaystyle 0=-2.6C_R+2.8C_R^2$
$\displaystyle 2.8C_R^2-2.6C_R=0$
Factor out a $\displaystyle 2C_R$
$\displaystyle 2C_R(1.4C_R-1.3)=0$
$\displaystyle 2C_R=0 \ or \ 1.4C_R=1.3$
Working with the latter equation:
$\displaystyle C_R=\frac{1.3}{1.4}= \frac{13}{14}$