Here Is A Problem- Find The Hcf Of: $\displaystyle m^4 - 4m^3 + 3m^2 + 2m -12 $ and $\displaystyle M^4 + 2m^2 + 9$.thanks In advance
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Originally Posted by sabyasachi Here Is A Problem- Find The Hcf Of: $\displaystyle m^4 - 4m^3 + 3m^2 + 2m -12 $ and $\displaystyle M^4 + 2m^2 + 9$.thanks In advance $\displaystyle m^4 - 4m^3 + 3m^2 + 2m -12 = (m^2 - 2m - 4)(m^2 - 2m + 3)$. $\displaystyle m^4 + 2m^2 + 9 = (m^2 - 2m + 3)(m^2 + 2m + 3)$. Therefore ......
thank you but can you explain how to factorise expressions like these?
Originally Posted by mr fantastic $\displaystyle m^4 - 4m^3 + 3m^2 + 2m -12 = (m^2 - 2m - 4)(m^2 - 2m + 3)$. $\displaystyle m^4 + 2m^2 + 9 = (m^2 - 2m + 3)(m^2 + 2m + 3)$. Therefore ...... Neither have real linear factors, so the obvious thing to do is look for irreducible quadratic factors ......
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