# Homework question

• May 27th 2008, 10:58 AM
reddy9
Homework question
Is "7th root" (3 over 2x^3y^5) when simplified equal to "7th root" (192x^4y^2) over 2xy? I just finished this homework question and was wondering if it was right thanks(Hi)
• May 27th 2008, 11:04 AM
Moo
Hello,

Quote:

Originally Posted by reddy9
Is "7th root" (3 over 2x^3y^5) when simplified equal to "7th root" (192x^4y^2) over 2xy? I just finished this homework question and was wondering if it was right thanks(Hi)

$\displaystyle \sqrt[7]{\frac{3}{2x^3y^5}}=? \frac{\sqrt[7]{192 x^4y^2}}{2xy}$

$\displaystyle \frac{\sqrt[7]{192 x^4y^2}}{2xy}=\sqrt[7] {\frac{192x^4y^2}{2^7x^7y^7}}=\sqrt[7]{\frac{3}{2x^3y^5}}$

So the answer is ... :D
• May 27th 2008, 11:09 AM
3n1gm4
Quote:

Originally Posted by reddy9
Is "7th root" (3 over 2x^3y^5) when simplified equal to "7th root" (192x^4y^2) over 2xy? I just finished this homework question and was wondering if it was right thanks(Hi)

$\displaystyle \sqrt[7]{\frac{192x^4y^2}{2xy}}$
$\displaystyle \sqrt[7]{\frac{3}{2 x^3 y^5}}$ ???