Thread: Linear equations in two variables add. help

Two points are given from each of two lines. Without graphing the points, determine wheather the lines are parallel, perpendicular or neither.
Line 1: (4, -6) (3, -2)
Line 2: (3, -1) (7, 0)
This is what I did.
-2 - (-6) = 4
3- 4 = -1

0 - (-1) = -1
7 - 3 = 4
Would it be perpendicular?

Write the slope-intercept form of each line. Then determine wheather the graphs of the lines are parallel, perpendicular, or neither.
4x + 2y = 8
2x + y = 1
This is what I did
4x + 2y = 8 / 2
y = -2x + 1
slope-intercept form: y= -2x + 4
slope-intercept form: y= -2x + 1
Is it parallel?
Thanks

Originally Posted by rowdy3

Two points are given from each of two lines. Without graphing the points, determine wheather the lines are parallel, perpendicular or neither.
Line 1: (4, -6) (3, -2)
Line 2: (3, -1) (7, 0)
This is what I did.
-2 - (-6) = 4
3- 4 = -1

0 - (-1) = -1 ==== should be +1
7 - 3 = 4
Would it be perpendicular?

Responding to your first question, you made a mistake on the slope for line 2.
Should be 1/4. So the lines are perpendicular.

Originally Posted by rowdy3

Write the slope-intercept form of each line. Then determine wheather the graphs of the lines are parallel, perpendicular, or neither.
4x + 2y = 8
2x + y = 1
This is what I did
4x + 2y = 8 / 2
y = -2x + 1
slope-intercept form: y= -2x + 4
slope-intercept form: y= -2x + 1
Is it parallel?
Thanks

You are correct. Slopes are the same (-2) so the lines are parallel