1. ## factoring

Sah...

First off, how do I factor $\displaystyle 8x^2+4x=0$, I also need to factor for x here. Oh, and how do I do fractions in Latex?

2. $\displaystyle 8x^{2}+4x=0$

$\displaystyle 4x(2x+1)=0$

$\displaystyle x=0$ , $\displaystyle x=-\frac{1}{2}$

Fraction: $\displaystyle \frac{1}{2}$ (check latex)

3. 8x^2 + 4x = 0

4x(2x + 1) = 0

4. firs thing you do is factor out the gcf 4x
then set both factors equal to 0
dose that help?

5. don't you mean you're trying to solve for x?
to factor, just pull out a gcf (greatest common factor) from both terms.

by that, i mean say you have $\displaystyle 9x^2 + 3x = 0$

Both have an x, so you can pull that out. and both are divisible by 3, so pull that out as well.

Now you have: $\displaystyle 3x(3x + 1) = 0$

So solve: $\displaystyle 3x = 0$ and $\displaystyle 3x + 1 = 0$

to make fractions, put \frac{numerator}{denominator}

6. Lol ty all... I completly blanked...

7. ## NEXT QUESTION! This is why I needed latex for fractions

$\displaystyle \frac{x^2+x-6}{x^2-x-2}$ * $\displaystyle \frac{x^2+5x+4}{x^2+2x-3}$

8. factor everything that you can to try to cross cancel.
remember, you can only do that on multiplication and division.