Find the x and y intercepts and slope (if they exist) for the line given.
-2x + y = 14
x intercept Would it be (-2,0)
y intercept Would it be ( 0,4)
Slope Would it be 2
The slope of a line is 1/3
What is the slope of a line parallel to the given line? Would it be 1/3
What is the slope of a line perpendicular to the given line? Would it be -1/3
What if the slope (if it exists) of a line given by the equation x = -5? Would it be undefined?
Thanks
These points aren't even on the line! How can they be intercepts??Originally Posted by rowdy3
You got the slope right, though.
$\displaystyle y = 2x + 14$
The x-intercept is where y = 0. Solve this for x.
The y-intercept is where x = 0. Solve this for y.
Yes to the first, no to the second. Two perpendicular lines have slopes that have the following property:
$\displaystyle m_1m_2 = -1$
So you know that $\displaystyle m_1 = 1/3$.
$\displaystyle \frac{1}{3} \cdot m_2 = -1$
Solve for $\displaystyle m_2$.
Yes. The slope of a line is rise/run. Consider two points on this line, say (-5, 1) and (-5, 6).
$\displaystyle \text{slope} = \frac{1 - 6}{-5 - (-5)} \to \frac{-5}{0}$
which is undefined.
-Dan
This is correct except for your x-intercept. Again, $\displaystyle \left(7,\;0\right)$ isn't even on the line (since $\displaystyle 0\neq2\cdot7 + 14$). Your method is fine, but you made a slight mistake when solving for $\displaystyle x$.
Write an equation of the line passing through the point (12, -10) having slope 4/3. Write your final answer in slope-intercept form.
Write an equation of the line passing through the point (0, 2) and parallel to the line x-y = 7. Write your final answer in slope-intercept form.
1. y+10= 4/3 ·(x- 12) My answer is y= 4/3·x -26
2. P(0,2) slope= 1--> y-2= 1(x-0) My answer is y= x + 2
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