Hi
I'm new and it's my first post
anyways can anyone help me to solve this Question it's really annoying
How fast?
Thanks
Let the average speed in first leg be v and let distance of first leg be x.
Then average speed in second leg is v + (v/10) = 11v/10 and distance of second leg is 2x.
Time to travel first leg: $\displaystyle t_1 = \frac{x}{v}$ .... (1)
Time to travel second leg: $\displaystyle t_2 = \frac{2x}{11v/10} = \frac{20 x}{11 v}$ .... (2)
Average speed for entire journey: $\displaystyle 9660 = \frac{3x}{t_1 + t_2}$ .... (3)
Substitute (1) and (2) into (3) and solve for v (note that the x's cancel out).
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