for what value of x is this true? and what are the steps to solve for it? thank you
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Originally Posted by Solan for what value of x is this true? and what are the steps to solve for it? thank you $\displaystyle 6x^4 - 2x^3 + 5$ is greater than zero for all real values of x. So the first thing you do is get rid of the absolute value signs. Then you simplify the inequality to $\displaystyle 4x^3 \geq 0$ .......
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