this is confusing. how do you expand this, any tips on how to expand trinomials?? x^3 + 8
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Originally Posted by algebra2 this is confusing. how do you expand this, any tips on how to expand trinomials?? x^3 + 8 This is already expanded. If you mean factor notice that this is the sum of cubes $\displaystyle x^3+2^3=(x+2)(x^2-2x+4)$ I hope this helps. Good luck.
could you explain it a bit
Originally Posted by algebra2 could you explain it a bit This is a formula that should be memorized $\displaystyle a^3+b^3=(a+b)(a^2-ab+b^2)$ for your problem we had $\displaystyle x^3+8=x^3+2^3$ a=x and b=2 so we get $\displaystyle x^3+2^3=(x+2)(x^2-2x+4)$ I hope this helps.
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