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  1. #1
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    solve equation

    I need help/answers for these questions it will be a huge faveur../

    1-Simplify:

    a: 3x(5x-2) -x (x(squared)-7) -x
    b: 5w-3(squared)-2+2w
    c: 8(x+3)-2(x-1)

    2-Solve:

    a: 8x-7=5(x+4)
    b: 8-2x=5
    c: 3x-5=7
    d: 7(3-p)=9-4p

    3-First three numbers in a sequence are 1, 2 and 4 exlapin why the fourth term would be 7 or 8..

    4-Factorise the expiression

    3x(squared)-15x

    5-Work out and leave answers as fraction

    2/3+3/5+7/4
    2 6/7 + 1 3/4
    2 1/2 + 1 3/4

    6-Square root of 1.44

    7- 1.3 squared=
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  2. #2
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    Quote Originally Posted by nasb View Post
    I need help/answers for these questions it will be a huge faveur../

    1-Simplify:

    a: 3x(5x-2) -x (x(squared)-7) -x
    b: 5w-3(squared)-2+2w
    c: 8(x+3)-2(x-1)

    2-Solve:

    a: 8x-7=5(x+4)
    b: 8-2x=5
    c: 3x-5=7
    d: 7(3-p)=9-4p

    3-First three numbers in a sequence are 1, 2 and 4 exlapin why the fourth term would be 7 or 8..

    4-Factorise the expiression

    3x(squared)-15x

    5-Work out and leave answers as fraction

    2/3+3/5+7/4
    2 6/7 + 1 3/4
    2 1/2 + 1 3/4

    6-Square root of 1.44

    7- 1.3 squared=
    Problem 1
    (a)
    $\displaystyle 3x(5x -2) - x(x^2 - 7) - x =$
    $\displaystyle 15x^2 - 6x - x^3 + 7x - x =$
    $\displaystyle 15x^2 - x^3 = x^2(15 - x)$

    (b)
    $\displaystyle (5w - 3)^2 - 2 + 2w =$
    $\displaystyle 25w^2 - 30w + 9 - 2 + 2w =$
    $\displaystyle 25w^2 - 28w + 7$

    (c)
    $\displaystyle 8(x + 3) - 2(x - 1) =$
    $\displaystyle 8x + 24 - 2x + 2 =$
    $\displaystyle 6x + 22$
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by nasb View Post
    2-Solve:

    a: 8x-7=5(x+4)
    b: 8-2x=5
    c: 3x-5=7
    d: 7(3-p)=9-4p
    These are all of the same type.
    $\displaystyle 8x - 7 =5(x + 4)$

    $\displaystyle 8x - 7 = 5 \cdot x + 5 \cdot 4$

    $\displaystyle 8x - 7 = 5x + 20$

    $\displaystyle 8x - 7 - 5x = 5x + 20 - 5x$

    $\displaystyle 3x - 7 = 20$

    $\displaystyle 3x - 7 + 7 = 20 + 7$

    $\displaystyle 3x = 27$

    $\displaystyle \frac{3x}{3} = \frac{27}{3}$

    $\displaystyle x = 9$

    The other three use the same basic pattern of solution. Try them again, step by step, using the above solution as a model. If you are still stuck on any of them, just let us know.

    -Dan
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by nasb View Post
    4-Factorise the expiression

    3x(squared)-15x
    Look for what is common to both terms.
    3 divides 15 evenly
    x divides x^2 evenly

    So
    $\displaystyle 3x^2 - 15x$

    $\displaystyle = 3x \cdot x - 3x \cdot 5$

    $\displaystyle 3x(x - 5)$

    -Dan
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  5. #5
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    Quote Originally Posted by topsquark View Post
    These are all of the same type.
    $\displaystyle 8x - 7 =5(x + 4)$

    $\displaystyle 8x - 7 = 5 \cdot x + 5 \cdot 4$

    $\displaystyle 8x - 7 = 5x + 20$

    $\displaystyle 8x - 7 - 5x = 5x + 20 - 5x$

    $\displaystyle 3x - 7 = 20$

    $\displaystyle 3x - 7 + 7 = 20 + 7$

    $\displaystyle 3x = 27$

    $\displaystyle \frac{3x}{3} = \frac{27}{3}$

    $\displaystyle x = 9$

    The other three use the same basic pattern of solution. Try them again, step by step, using the above solution as a model. If you are still stuck on any of them, just let us know.

    -Dan
    can you give answers for more please?
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