(y+1)^2 over y^2 + y divided by y^2 minus 1 over y^2
I blame Canada!
$\displaystyle \frac {\frac {(y + 1)^2}{y^2 + y}}{\frac {y^2 - 1}{y^2}} = \frac {(y + 1)^2}{y^2 + y} \cdot \frac {y^2}{y^2 - 1}$
$\displaystyle = \frac {(y + 1)^2}{y(y + 1)} \cdot \frac {y^2}{(y + 1)(y - 1)}$
$\displaystyle = \frac {y^2 (y + 1)^2}{y(y + 1)^2 (y - 1)}$
$\displaystyle = \frac y{y - 1}$