This is for review and I can't remember this.
What is the equation of a parabola with focus (6, -10) and directrix x = -2?
Personally I prefer the long way (no surprise to anyone who knows me). A parabola is defined as the locus of points such that the distance between the focus and parabola is the same as the distance between the parabola and the directrix. So
$\displaystyle \sqrt{(x - 6)^2 + (y + 10)^2} = x + 2$
-Dan
See this.
I prefer the definition I used because I can get equations for parabolas with axes of symmetry that aren't "nice."
In any event the directrix here is parallel to the y axis, so we can use the form
$\displaystyle (y - k)^2 = \pm 4p(x - h)$
p is the twice the distance between the directrix and the focus, so p = 4. The vertex is half way between the directrix and the focus so it is at V(2, -10). So the equation will be
$\displaystyle (y + 10)^2 = \pm 16(x - 2)$
Finally, we know that the focus is to the right of the directrix, so this parabola opens to the right. Thus we choose the + sign:
$\displaystyle (y + 10)^2 = 16(x - 2)$
Edit:
You can solve for the answer using my method:
$\displaystyle \sqrt{(x - 6)^2 + (y + 10)^2} = x + 2$
$\displaystyle (x - 6)^2 + (y + 10)^2 = (x + 2)^2$
$\displaystyle (y + 10)^2 = (x + 2)^2 - (x - 6)^2 = (x^2 + 4x + 4) - (x^2 - 12x + 36)$
$\displaystyle (y + 10)^2 = 16x - 32$
$\displaystyle (y + 10)^2 = 16(x - 2)$
-Dan