Hello,
I'm having problems with completing the square can anyone comment on my working?
2x^2 - 3x -1 = 0
2(x -3/4)^2 -(-3/4)^2 - 1/2 = 0
2(x - 3/4)^2 -17/16 =0
2(x - 3/4)^2 = 17/16
(x - 3/4)^2 = 17/32
x - 3/4 = +-√17/32
x = 3/4 +-√17/32
Thanks in advance. Please post solution if I am incorrect.
Second attempt
2x^2 - 3x -1 = 0
2(x -3/4)^2 -(-3/4)^2 - 1/2 = 0
2((x - 3/4)^2) -17/8 =0
2(x - 3/4)^2 = 17/8
(x - 3/4)^2 = 17/16
x - 3/4 = +-√17/16
x = 3/4 +-√17/16
Is my teacher wrong in stating that it is x = 3/4 +-√17/4?
Just to add my 2 cents......
1. First transpose the -1 to the right side of the equation.
2. Divide each term by 2
3. Take half of the coefficient of x, square it and add it to both sides.
4. Noting the perfect square trinomial on the left:
5. Take the square root of both sides:
6. Finally,