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Math Help - Finding the vertex and x-intercepts of an equation

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    Finding the vertex and x-intercepts of an equation

    How do i find the vertex and the x-intercepts of y=2(x-3)(x+1)?
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    Quote Originally Posted by scorpio View Post
    How do i find the vertex and the x-intercepts of y=2(x-3)(x+1)?
    The equatio describes a parabola opening up.

    You find the x-intercepts if y = 0. Since you have the equation in factored form you can read the values of the x-intercepts directly: x = 3 or x = -1

    Expand the brackets and rewrite the equation in vertex-form:

    y = 2(x - 2x - 3) = 2(x-2x+1 - 1 - 3) = 2(x-1) - 8

    Therefore the vertex has the coordinates: V(1, -8)
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