Originally Posted by **earboth**

Hi, kwtolley,

calculate first the specific resistance $\displaystyle \rho$ form:

$\displaystyle R=\frac{\rho\cdot l}{A}$ where the resistance R is measured in $\displaystyle \Omega$, the length l in m and the area A in square-millimeters.

You'll get:

$\displaystyle 36\Omega=\frac{\rho \cdot 20 m}{\pi \cdot (3mm)^2}$ $\displaystyle \Longrightarrow\ \rho=\frac{36\Omega \cdot\pi\cdot 9 mm^2}{20m}$

Now plug in the values you know and you'll get:

$\displaystyle R=\frac{\frac{36\Omega \cdot\pi\cdot 9 mm^2}{20m}\cdot 60 m}{\pi\cdot 36 mm^2}$$\displaystyle \ =\ 27\Omega$

Bye

EB