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Math Help - Value of the constant

  1. #1
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    Post Value of the constant

    Express the following statement as a formula with the value of the constant of proportionality determined with the given conditions: w variers directly as x and inversely as the square of y. If x=15 and y=5, then w=36. Ok my anwser is w=36 x/y^2 is this right I don't think so. Thanks for any help given.
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  2. #2
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    Hello, kwtolley!

    Express the following statement as a formula with the value of the constant of proportionality
    determined with the given conditions:

    w variers directly as x and inversely as the square of y.
    If x=15 and y=5, then w=36.

    Ok, my answer is: w = \frac{36x}{y^2} . . . Is this right? . . . sorry, no
    It looks like you started correctly: . w \:= \:\frac{kx}{y^2}

    We're told that: . x = 15,\;y=5,\;w = 36

    Plug them in: . 36 = \frac{k\cdot15}{5^2}\quad\Rightarrow\quad k = 60

    Therefore: . w \:=\:\frac{60x}{y^2}
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  3. #3
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    thank you note

    thanks for checking my answer
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