Solve:

x^4-10x^3+42x^2-82x+65=0 the product of two of the roots of this equation is 13. The answers are complex numbers.

Thanks for helping me(Rofl)

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- May 18th 2008, 03:39 AMAnand Parikhzeros of polynomials
Solve:

x^4-10x^3+42x^2-82x+65=0 the product of two of the roots of this equation is 13. The answers are complex numbers.

Thanks for helping me(Rofl) - May 18th 2008, 04:22 AMmr fantastic
- May 18th 2008, 06:40 AMCaptainBlack
- May 18th 2008, 08:01 AMSoroban
Hello, Anand Parikh!

Quote:

Solve: .

The product of two of the roots of this equation is 13.

The roots are complex numbers.

lucky . . .*very*

Since the product of two roots is 13,

. . I**guessed**that the roots were: .

If the roots are: .

. . then: . .are factors of

Hence: . .is a factor of

. . But does**not**divide

If the roots are: .

. . then: . .are factors of

Hence: . .is a factor of

. . And we have: .