Hello guys just a few questions
1.) Factorise completely 2x^3 - 20x^2 + 46x - 28
here i took out the common factor to give 2(x^3 - 10x^2 + 23x - 14)
now when i began trying factors i wasnt sure whether to leave the 2 outside like so: 2((1)^3 - 10(1)^2 + 23(1) - 14))
or just (1)^3 - 10(1)^2 + 23(1) -14
now the second part is long division... do i leave the two outside when long dividing or do i have to expand i back into the sum?
The division of by will give something like hence : has been factored too. That's why you only need to factor .
Is it clearer ?
I don't understand what you mean.just for general knowledge, if u had something like this : 3(2x-1)^3 -4 could u times the 3(2x-1)^3 by the three first, or do u have to cube it first?