Well exams in 2 days and i forgot how to factorise. I decided to do some examples from da book and i saw this one
4(p-q) + (p-q)^3 (^ = to the power btw:P)
I checked the back and it told me that the answer is (p-q)[4+(p-q)^2] That makes no sense whatsoever anyway we would left with pq^2 and qp^2 ffs i need an A badly and this question is making me nuts help ?!
thanks for help that makes still no sense i wasnt in when we did that in school .
Could you tell me whats the function of a square bracket in factorising please?
wait wait 4(p-q)+ (p-q)(p-q)2 if we are multiplying than it should be 4(p-q) + p3-q3 + we would still have pq3 qp3 ??
You extract a common factor of a sum (or a product as well).
If you have chosen for the common factor (or you are told what the common factor has to be) then you must divide each summand by the factor and the result of the division is written into the bracket.
I take as common factor
Simplify the fractions and you'll get the final result:
You even can factor out a factor which doesn't appear in the sum:
Factor out x of
Maybe this helps you a little bit(?)