Hi just some algebra problems I got a bit confused about...

Expand and simplify (3a-b)(3b-a)

I got to: 9ab-3a-3b+ab?!

x²+5x

------

x²-25

And for this one I got to:

x²+5x

-----------

(x+5)(x-5)

Also:

x²+3x-10

-----------

x²+7x+10

And I got to:

x-2

----

x+2

And find values of p and q in the identity x²+6x+10=(x+p)² + p

Hence or otherwise, show that there are no real solutions of the equation x²+6x+10=0

Thanks