Hi just some algebra problems I got a bit confused about...
Expand and simplify (3a-b)(3b-a)
I got to: 9ab-3a-3b+ab?!
And for this one I got to:
And I got to:
And find values of p and q in the identity x²+6x+10=(x+p)² + p
Hence or otherwise, show that there are no real solutions of the equation x²+6x+10=0