Hello,

Yes... but 9ab+ab=... ?

Hey, note thatx²+5x

------

x²-25

And for this one I got to:

x²+5x

-----------

(x+5)(x-5)

OkAlso:

x²+3x-10

-----------

x²+7x+10

And I got to:

x-2

----

x+2

Hmm...And find values of p and q in the identity x²+6x+10=(x+p)² + q

Hence or otherwise, show that there are no real solutions of the equation x²+6x+10=0

Is it possible ?