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Math Help - Algebra simplify

  1. #1
    Junior Member Turple's Avatar
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    Nov 2007
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    Question Algebra simplify

    Hi just some algebra problems I got a bit confused about...

    Expand and simplify (3a-b)(3b-a)

    I got to: 9ab-3a-3b+ab?!

    x+5x
    ------
    x-25

    And for this one I got to:

    x+5x
    -----------
    (x+5)(x-5)

    Also:

    x+3x-10
    -----------
    x+7x+10

    And I got to:

    x-2
    ----
    x+2

    And find values of p and q in the identity x+6x+10=(x+p) + p

    Hence or otherwise, show that there are no real solutions of the equation x+6x+10=0

    Thanks
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  2. #2
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
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    Hello,

    Quote Originally Posted by Turple View Post
    Hi just some algebra problems I got a bit confused about...

    Expand and simplify (3a-b)(3b-a)

    I got to: 9ab-3a-3b+ab?!
    Yes... but 9ab+ab=... ?

    x+5x
    ------
    x-25

    And for this one I got to:

    x+5x
    -----------
    (x+5)(x-5)
    Hey, note that x^2+5x=x(x+5)

    Also:

    x+3x-10
    -----------
    x+7x+10

    And I got to:

    x-2
    ----
    x+2
    Ok

    And find values of p and q in the identity x+6x+10=(x+p) + q

    Hence or otherwise, show that there are no real solutions of the equation x+6x+10=0
    Hmm...

    x^2+6x+10=(x^2+6x+9)+1=(x+3)^2+1

    x^2+6x+10=0 \Longleftrightarrow (x+3)^2+1=0 \Longleftrightarrow (x+3)^2=-1

    Is it possible ?
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  3. #3
    Junior Member
    Joined
    Apr 2008
    Posts
    42
    Quote Originally Posted by Moo View Post
    Hmm...

    x^2+6x+10=(x^2+6x+9)+1=(x+3)^2+1

    x^2+6x+10=0 \Longleftrightarrow (x+3)^2+1=0 \Longleftrightarrow (x+3)^2=-1

    Is it possible ?
    I don't see why not!
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