# Math Help - radical expressions/exponents.

mmkay so im new at this..but i cant figure these out to save my life.. and i have a test in about six hours which is what either make me pass or fail the class..so herei go:

simplify:

the cube root of 'A' to the fourth over nine.

2. Originally Posted by morgan.
mmkay so im new at this..but i cant figure these out to save my life.. and i have a test in about six hours which is what either make me pass or fail the class..so herei go:

simplify:

the cube root of 'A' to the fourth over nine.
You mean $(\sqrt[3]{A})^{\frac49}$?

$(\sqrt[3]{A})^{\frac49} = ((A)^{\frac13})^{\frac49} = (A)^{{\frac13}{\frac49}} = A^{\frac4{27}}$

But I doubt this is a simplification... looks like a complication....

3. How do we know it's not:

$\frac{(\sqrt[3]a)^4}{9}$