# algebra word problem

• May 14th 2008, 06:57 PM
fishnprincipal
algebra word problem
Irv's cycle rental shop, Irv rents all kinds of cycles: unicycles,tandem bikes, regular bikes, and even tricycles for little kids. He parks all the cycles in front of his shop with a helmet for each rider strapped to the cycles. THis morning Irv counted 57 helmets and 115 wheels parked in front of his store. He knows he has an equal number of unicycles and tandem bikes. He also knows that he has 32 regular bikes. How many unicycles, tandem bikes, and tricycles does Irv have? (a tandem bike has two helmets)
• May 14th 2008, 08:23 PM
Soroban
Hello, fishnprincipal!

Quote:

At Irv's cycle rental shop, he rents all kinds of cycles:
unicycles, tandem bikes, regular bikes, and even tricycles for little kids.
He has a helmet for each rider strapped to the cycles.
This morning Irv counted 57 helmets and 115 wheels parked in front of his store.
He knows he has an equal number of unicycles and tandem bikes.
He also knows that he has 32 regular bikes.
How many unicycles, tandem bikes, and tricycles does Irv have?

$\displaystyle \begin{array}{c|cc} & \text{Helmets} & \text{Wheels} \\ \hline \text{Unicycles (U)} & 1 & 1 \\ \text{Tandems (T)} & 2 & 2 \\ \text{Bicycle (B)} & 1 & 2 \\ \text{Tricycles (R)} & 1 & 3 \\ \hline \text{Totals:} & 57 & 115 \end{array}$

We have: . $\displaystyle U + 2T + B + R \:=\:57$
. . . and: .$\displaystyle U + 2T + 2B + 3R \:=\:115$

We are told that: .$\displaystyle U = T,\:B = 32$

The equations becomes: .$\displaystyle \begin{array}{cccccccc} U + 2U + 32 + R &=&57 & \Rightarrow & 3U + R &=&25 & {\color{blue}[1]}\\ U + 2U + 64 + 3R &=&115 & \Rightarrow & 3U + 3R &=&51 & {\color{blue}[2]} \end{array}$

Subtract [1] from [2]: .$\displaystyle 2R \:=\:26 \quad\Rightarrow\quad\boxed{ R \:=\:13}$

Substitute into [1]: .$\displaystyle 3U + 13 \:=\:25 \quad\Rightarrow\quad\boxed{U \:=\:4} \quad\Rightarrow\quad\boxed{T \:=\:4}$

Therefore: .4 unicycles, 4 tandems, and 13 tricycles.