2N$\displaystyle

^{\frac{2}{5}}

$h$\displaystyle

^{\frac{3}{5}}

$

do I just multiply 2 X N then take the answer and raise to the power of 2/5

Or do I raise N to the power of 2/5 and then X by 2

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- May 14th 2008, 12:49 AMGraemesimplify exponents
2N$\displaystyle

^{\frac{2}{5}}

$h$\displaystyle

^{\frac{3}{5}}

$

do I just multiply 2 X N then take the answer and raise to the power of 2/5

Or do I raise N to the power of 2/5 and then X by 2 - May 14th 2008, 01:33 AMReckoner
Do you mean $\displaystyle 2N^{\frac25}h^{\frac35}$? If so, exponentiation takes precedence over multiplication, so you have to take $\displaystyle N$ to the $\displaystyle \frac25$ before you multiply by two, unless the problem is written with the $\displaystyle 2N$ in parentheses.

- May 14th 2008, 01:38 AMGraeme
Thanks

So if I raise N to the power of 2/5 then x 2 =answer a

Then h to the power 3/5 =answer b

then a x b does that look correct - May 14th 2008, 01:41 AMReckoner