# Math Help - solve absolute value

1. ## solve absolute value

|2x-3/9|=5

2. $|2x-3/9|=5$ Is equivalent to say that $-5<2x-\frac{3}{9}<5$, or $-5+\frac{3}{9}<2x<5+\frac{3}{9}$, or $\frac{{-5}+{\frac{3}{9}}}{2}. Almost done, I let you simplify the fractions.

3. Hello, super9xman!

Solve: . $\left| \frac{2x-3}{9}\right|\:=\:5$

We have: . $\begin{Bmatrix}\dfrac{2x-3}{9} & = & \text{-}5 \\ \\ \dfrac{2x-3}{9} &=& 5 \end{Bmatrix}
. $\Rightarrow\quad\begin{Bmatrix}2x &=&\text{-}42 \\ \\ 2x &=&48 \end{Bmatrix}\quad\Rightarrow\quad \begin{Bmatrix}x &=&\text{-}21 \\ \\ x&=& 24\end{Bmatrix}$