neefd help fast

http://img404.imageshack.us/img404/3...titled33ix.jpg

Printable View

- Jun 27th 2006, 02:48 PMAHDDMneed help in less than 3hrs circle
neefd help fast

http://img404.imageshack.us/img404/3...titled33ix.jpg - Jun 27th 2006, 07:20 PMSoroban
Hello, AHDDM!

We are given: and

Let , then

is inscribed in a semicircle.

. . Hence, is a right triangle.

is the altitude to the hypotenuse of a right triangle.

Theorem: The altitude to the hypotenuse of a right triangle is

. . the mean proportional of the two segments of the hypotenuse.

Hence: .

We have the quadratic: .

. . which factors: .

. . and has the positive root: .

Therefore: . cm.

- Jun 29th 2006, 10:25 PMAHDDM
thx 4 the reply

i keep frogetting to subtitute gotta learn to remeber