(x-2)(x^2 + 3x) + 5x - 3 = 0
Any suggestions on how to solve for x? Thanks,
Jim
0. Graph the funktion to get the number of x-intercepts.
1. Expand the brackets:
$\displaystyle x^3+x^2-x-3=0$
2. Use Cardano's formula (kind of tricky) or
3. Use Newton-Raphson method to get an approximate solution.
4. There is only one real solution.
5. For your confirmation only: $\displaystyle x \approx 1.359304085$