Thread: Solve for x

(x-2)(x^2 + 3x) + 5x - 3 = 0

Any suggestions on how to solve for x? Thanks,

Jim

Originally Posted by Jim Newt

(x-2)(x^2 + 3x) + 5x - 3 = 0

Any suggestions on how to solve for x? Thanks,

Jim

0. Graph the funktion to get the number of x-intercepts.

1. Expand the brackets:



2. Use Cardano's formula (kind of tricky) or

3. Use Newton-Raphson method to get an approximate solution.

4. There is only one real solution.

5. For your confirmation only:

Simplifies to

No rational roots.

One irrational root
Two complex roots

Thanks!

Originally Posted by earboth

0. Graph the funktion to get the number of x-intercepts.

1. Expand the brackets:



2. Use Cardano's formula (kind of tricky) or

3. Use Newton-Raphson method to get an approximate solution.

4. There is only one real solution.

5. For your confirmation only:

Use a combination of intuitiveness and the intermediate value theorem to get a good guess to start Newton's method