If there is no , you can just insert a into the equation for yourself.
So it becomes:
Can you go on from here? Or do you want me to go further with it?
I have got used to the standard division of polynomials ie divide x^3 + 2x^2 + 2x + 4 = 0 by (x-2).
This seems to flow well and the answer is easy to find. BUT, what happens if there is no coefficient for x^2.
My question is:
show that (x-2) is a factor of x^3 - 7x + 6 (which I have done).
It then goes on to say solve the equation f(x) = 0 ??????
Normally I would divide f(x) by long division and then factorise the answer to get something like (x-2)(x-?)(x+?)=0
Am I missing something very simple here?
Any help would be appreciated. Rob
And the maths stuff comes from what's called Latex, I'm onlt getting used to it myself to be honest, but this is what I use when I'm typing out stuff:
Just click on the link in MathMan's first post, and it'll bring up all the Latex rules in Adobe for you