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Math Help - Division of Polynomials?

  1. #1
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    Division of Polynomials?

    Hi there.
    I have got used to the standard division of polynomials ie divide x^3 + 2x^2 + 2x + 4 = 0 by (x-2).
    This seems to flow well and the answer is easy to find. BUT, what happens if there is no coefficient for x^2.

    My question is:
    show that (x-2) is a factor of x^3 - 7x + 6 (which I have done).

    It then goes on to say solve the equation f(x) = 0 ??????

    Normally I would divide f(x) by long division and then factorise the answer to get something like (x-2)(x-?)(x+?)=0

    Am I missing something very simple here?

    Any help would be appreciated. Rob
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  2. #2
    Junior Member simplysparklers's Avatar
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    Hi rsmith!

    If there is no x^2, you can just insert a 0x^2 into the equation for yourself.

    So it becomes:
    (x^3+0x^2-7x+6) / (x-2)

    Can you go on from here? Or do you want me to go further with it?
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  3. #3
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    Thanks for that. I'll have a go and you can check it if that's ok with you?

    PS: where do you type all of the maths symbols, it's a pain if they're not used.
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  4. #4
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    x^2 + 2x - 3 I think that's right. Thanks.
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  5. #5
    Junior Member simplysparklers's Avatar
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    No problem!

    And the maths stuff comes from what's called Latex, I'm onlt getting used to it myself to be honest, but this is what I use when I'm typing out stuff:
    http://www.mathhelpforum.com/math-he...-tutorial.html

    Just click on the link in MathMan's first post, and it'll bring up all the Latex rules in Adobe for you
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  6. #6
    Junior Member simplysparklers's Avatar
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    That's what I got anyway!!
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