I have got used to the standard division of polynomials ie divide x^3 + 2x^2 + 2x + 4 = 0 by (x-2).
This seems to flow well and the answer is easy to find. BUT, what happens if there is no coefficient for x^2.
My question is:
show that (x-2) is a factor of x^3 - 7x + 6 (which I have done).
It then goes on to say solve the equation f(x) = 0 ??????
Normally I would divide f(x) by long division and then factorise the answer to get something like (x-2)(x-?)(x+?)=0
Am I missing something very simple here?
Any help would be appreciated. Rob