# Reduction math problem

• May 12th 2008, 08:32 AM
David T
Reduction math problem
Hi, I'm trying to solve this very simple reduction problem, but I just can't get my head around it.

Here it goes:

xy + x^2 / xy

It's supposed to be reduced, and my best bet is that the solution is
x/y but I'm not sure at all..

Any help appreciated! :)
• May 12th 2008, 08:38 AM
abender
xy + x^2 / xy

I will assume that you mean xy + ((x^2) / xy)

If that is the case, xy + x/y -----> x(y + (1/y)) this last one not as nice..

Is this what you wanted? Explain please.

-Andy
• May 12th 2008, 08:55 AM
Mathstud28
Quote:

Originally Posted by David T
Hi, I'm trying to solve this very simple reduction problem, but I just can't get my head around it.

Here it goes:

xy + x^2 / xy

It's supposed to be reduced, and my best bet is that the solution is
x/y but I'm not sure at all..

Any help appreciated! :)

$xy+\frac{x^2}{xy}\Rightarrow{xy+\frac{x}{y}}$

Combining fractions we get $\frac{xy^2+x}{y}=\frac{x(y^2+1)}{y}$
• May 12th 2008, 09:14 AM
Moo
Quote:

Originally Posted by David T
Hi, I'm trying to solve this very simple reduction problem, but I just can't get my head around it.

Here it goes:

xy + x^2 / xy

It's supposed to be reduced, and my best bet is that the solution is
x/y but I'm not sure at all..

Any help appreciated! :)

Ok, I won't do it the way the other ones did it (Rofl)

$\frac{xy+x^2}{xy}=\frac{x(y+x)}{xy}=\frac{y+x}{y}= 1+\frac xy$

:D
• May 12th 2008, 09:44 AM
Mathstud28
Quote:

Originally Posted by Moo
Ok, I won't do it the way the other ones did it (Rofl)

$\frac{xy+x^2}{xy}=\frac{x(y+x)}{xy}=\frac{y+x}{y}= 1+\frac xy$

:D

You know what? You are actually probably right in guessing that is what the poster meant. Sharp eyes (Wink)
• May 12th 2008, 09:46 AM
Moo
Quote:

Originally Posted by Mathstud28
You know what? You are actually probably right in guessing that is what the poster meant. Sharp eyes (Wink)

It's not me, it's you who look for complicated things :D

However, I agree on one point : the OP didn't write the text clearly...
• May 13th 2008, 06:21 AM
David T
Thanks for all the input guys!

Moo your answer was what I was looking for, thanks a lot! :)