# College Algebra

• Jun 26th 2006, 08:05 PM
Brooke
College Algebra
identify which of the numbers -1, 1, 5/2, -2/5, 3/2, and 2/5 are roots of the polynomial equation 10x raised to the 4th -19x raised to the third -4x raised to second+19x-6.

determine which of the following correctly uses the intermediate value theroem to show that the graph of the function has a zero in the given interval. Find the value of the zero to tow decimal places.
f(x)= 2x raised to the third +3x raised the second - 10 x -4; [-3,-2]

a: f(-2)=12>f(-3)=-1 (-4.00,0)
b: f(-3)=-1<0 and f(-2)=12>0 (-2.96, 0)
c: f(-3)=-1<0 and f(-2) =12>o (-4.00,0)
d: f(-2)= 12>f(-3)=-1 (-2.96,0)
• Jun 27th 2006, 07:54 AM
CaptainBlack
Quote:

Originally Posted by Brooke
identify which of the numbers -1, 1, 5/2, -2/5, 3/2, and 2/5 are roots of the polynomial equation 10x raised to the 4th -19x raised to the third -4x raised to second+19x-6.

Which of \$\displaystyle -1,\ 1,\ 5/2,\ -2/5,\ 3/2,\ 2/5\$ are roots of:

\$\displaystyle 10x^4-19x^3-4x^2+19x-6\$

This at one level just involves trying each of the values:

\$\displaystyle x=-1,\ 1,\ 5/2,\ -2/5,\ 3/2,\ 2/5\$

to see which of these result in the polynomial evaluating to \$\displaystyle 0\$.
Doing this we see that the roots are \$\displaystyle -1,\ 1,\ 3/2,\ 2/5\$.

RonL