Hi again guys!
Once again I need help with what should be relatively simple, because once again my maths textbook refuses to explain things properly
Ok so its about the Sum to Infinity of a Geometric Series:
In a certain geometric sequence the first term exceeds the second term by 32 and the sum of the second and third terms is 48. Find the infinite sum of the sequence.
I thought I had the answer, but turns out I was way off-I'll give you what I got and I would appreciate it if someone could please tell me where I went wrong. I got: a= 192/7, r=-1/6
Because a=32/1-r and a= 48/r-r^2. Since a=a, 32/1-r = 48/r-r^2
I solved for r by using the Quadractic formula.