Rationalize the denominator

**silencecloak** · May 9th 2008, 01:27 PM

This one seems exceptionally hard :/

So far I have it down to

But I'm not sure if I'm even going the right route or not

Thanks in advance

ps: answer is x to the power of 1/5

**Moo** · May 9th 2008, 01:32 PM

Hello,

Originally Posted by silencecloak

This one seems exceptionally hard :/

So far I have it down to

But I'm not sure if I'm even going the right route or not

Thanks in advance

ps: answer is x to the power of 1/5

Do you know about this definition ?

$\sqrt[n]{x}=x^{\frac 1n}$ ?

This would help here !

$\sqrt[a]{x^b}=(x^b)^{\frac 1a}=x^{\frac ba}$

**o_O** · May 9th 2008, 01:34 PM

$a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = \left(\sqrt[n]{a}\right)^{m}$

Think in fractional exponents by using the above relations. Then, you should be able to simplify with your exponent laws - specifically: $\frac{a^{m}}{a^{n}} = a^{m-n}$

**silencecloak** · May 9th 2008, 01:39 PM

Ah well that wasn't so bad!

Do either of you know a site that well, lists all or a lot of the pre calculus and algebra rules?

That would help tons!

Thanks

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