Math Help - Re-arranging and solving for q

1. Re-arranging and solving for q

35q^(-3/5)=-21q^(-8/5)-((-21q^8/5)*35q^(-3/5))

Re-arrange and solve for q. I did it but got some mad answer.

2. How 'bout showing us how far you got!

3. Hello,

Originally Posted by jdizzle1985
35q^(-3/5)=-21q^(-8/5)-((-21q^8/5)*35q^(-3/5))

Re-arrange and solve for q. I did it but got some mad answer.
Let's put it all in one side :

$35q^{-3/5}+21q^{-8/5}+({\color{red}(-21q^{8/5})*35q^{-3/5}})=0$

Look at the red thing

$-21q^{8/5}*35q^{-3/5}=-(21*35)q^{8/5-3/5}=-21*35 q^1=-21 \cdot 35 \cdot q$

Hence the equation is now :

$35q^{-3/5}+21q^{-8/5}-21 \cdot 35 \cdot q=0$

Multiplying everything by $q^{8/5}$, we get :

$35q^1+21q^0-21\cdot 35 \cdot q^{13/5}=0$

$35q+21-21\cdot 35 \cdot q^{13/5}=0$

$35q^{-3/5}+21q^{-8/5}+({\color{red}(-21q^{8/5})*35q^{-3/5}})=0$