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Math Help - Re-arranging and solving for q

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    Re-arranging and solving for q

    35q^(-3/5)=-21q^(-8/5)-((-21q^8/5)*35q^(-3/5))

    Re-arrange and solve for q. I did it but got some mad answer.
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  2. #2
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    How 'bout showing us how far you got!
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  3. #3
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    Hello,

    Quote Originally Posted by jdizzle1985 View Post
    35q^(-3/5)=-21q^(-8/5)-((-21q^8/5)*35q^(-3/5))

    Re-arrange and solve for q. I did it but got some mad answer.
    Let's put it all in one side :

    35q^{-3/5}+21q^{-8/5}+({\color{red}(-21q^{8/5})*35q^{-3/5}})=0

    Look at the red thing

    -21q^{8/5}*35q^{-3/5}=-(21*35)q^{8/5-3/5}=-21*35 q^1=-21 \cdot 35 \cdot q

    Hence the equation is now :

    35q^{-3/5}+21q^{-8/5}-21 \cdot 35 \cdot q=0

    Multiplying everything by q^{8/5}, we get :

    35q^1+21q^0-21\cdot 35 \cdot q^{13/5}=0

    35q+21-21\cdot 35 \cdot q^{13/5}=0

    I got mad answers too
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  4. #4
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    Quote Originally Posted by Moo View Post
    35q^{-3/5}+21q^{-8/5}+({\color{red}(-21q^{8/5})*35q^{-3/5}})=0

    Look at the red thing

    "Look at the red thing?" hahahaha! That was my favorite part!
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