# Math Help - Need answer checked

$\frac{5x-5}{6} \cdot \frac{x}{x^2-x} = \frac{5x^2-5x}{6x^2-6x} = x^2+x$

2. Nope, I am sorry to say.

factor:

$\frac{5(x-1)}{6}\cdot\frac{x}{x(x-1)}=\frac{5}{6}$

3. Originally Posted by Jarod_C

$\frac{5x-5}{6} \cdot \frac{x}{x^2-x} = \frac{5x^2-5x}{6x^2-6x} = x^2+x$
Your problem can be found here...

$\frac{5x^2-5x}{6x^2-6x} = x^2+x$

You took out the coefficients instead of the variables. The end result should be five sixths as Galactus showed you.