Need answer checked

**Jarod_C** · May 8th 2008, 12:47 PM

Thanks in advance.

$\frac{5x-5}{6} \cdot \frac{x}{x^2-x} = \frac{5x^2-5x}{6x^2-6x} = x^2+x$

**galactus** · May 8th 2008, 12:48 PM

Nope, I am sorry to say.

factor:

$\frac{5(x-1)}{6}\cdot\frac{x}{x(x-1)}=\frac{5}{6}$

**colby2152** · May 9th 2008, 06:44 AM

Originally Posted by Jarod_C

Thanks in advance.

$\frac{5x-5}{6} \cdot \frac{x}{x^2-x} = \frac{5x^2-5x}{6x^2-6x} = x^2+x$

Your problem can be found here...

$\frac{5x^2-5x}{6x^2-6x} = x^2+x$

You took out the coefficients instead of the variables. The end result should be five sixths as Galactus showed you.

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