[SOLVED] Confirm my answer too please!

I just wanted to make sure that I had done my math correctly on this question:


Solve by graphing(I can't show the graphs, but the problem and my working is as follows)

Question
3x+2y=8
6x+4y=16

Working
3x+2y=8
6x+4y=16

I put 3x+2y=8 into terms of y so it became 2y=8-3x.

Then I divided that equation by 2 so it became:y=4-3/2x

I replaced x with values from 0-2 and worked the problems out, resulting in this: x=0 y=4
x=1 y=5/2 or 2 1/2
x=2 y=1

I repeated the process with the second string and came out with this:
x=0 y=4
x=1 y=5/2 or 2 1/2
x=2 y=1

since the solutions were identical I decided that the lines coincide.

_________________________________


Thank you in advance for all your help.

Quote:

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Originally Posted by haflore

I just wanted to make sure that I had done my math correctly on this question:


Solve by graphing(I can't show the graphs, but the problem and my working is as follows)

Question
3x+2y=8
6x+4y=16

Working
3x+2y=8
6x+4y=16

I put 3x+2y=8 into terms of y so it became 2y=8-3x.

Then I divided that equation by 2 so it became:y=4-3/2x

I replaced x with values from 0-2 and worked the problems out, resulting in this: x=0 y=4
x=1 y=5/2 or 2 1/2
x=2 y=1

I repeated the process with the second string and came out with this:
x=0 y=4
x=1 y=5/2 or 2 1/2
x=2 y=1

since the solutions were identical I decided that the lines coincide.

_________________________________


Thank you in advance for all your help.

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refer to masters comment below

Your second linear equation is a multiple of your first linear equation. Each term was multiplied by 2. Multiples of a linear equation always graph the same line.

I really appreciate your help, guys, thanks!(Clapping)