1. ## solving equation

Hi i have some problem solving this equation, I'm not sure its even possible but if it is it would give the answer to my task. so here it is:

$590^2+y^2=(1132+x)^2$

A fast answer here would be very much appreciated since I'm in a bit of a hurry

Greetings from Rickard Liljeros

OBs edit the "^2" in the end should be outside the ")"

2. You can solve for x in terms of y or you can solve for y in terms of x, but you cannot come up with a unique value for x and y.

3. Originally Posted by liljeros
Hi i have some problem solving this equation, I'm not sure its even possible but if it is it would give the answer to my task. so here it is:

$590^2+y^2=(1132+x)^2$

A fast answer here would be very much appreciated since I'm in a bit of a hurry

Greetings from Rickard Liljeros

OBs edit the "^2" in the end should be outside the ")"
$y = \pm 3456, x = 2374, -4368$

4. Originally Posted by Isomorphism
$y = \pm 3456, x = 2374, -4368$
How can we know we're looking for integer solutions ?

5. Originally Posted by masters
You can solve for x in terms of y or you can solve for y in terms of x, but you cannot come up with a unique value for x and y.
Thank you! Well then I must have done wrong when trying to solve my task. Maybe you could help me with how to think?

It is about a skiing slope and i get some numbers but not all, The task is to get the length of one part of the slope, will make a picture that looks like the one in the paper:

I should get X.

m= meters (length)

6. Originally Posted by liljeros
Thank you! Well then I must have done wrong when trying to solve my task. Maybe you could help me with how to think?

It is about a skiing slope and i get some numbers but not all, The task is to get the length of one part of the slope, will make a picture that looks like the one in the paper:

I should get X.

m= meters (length)
Well, you can use Thalès theorem :

AC/AB=AH/AM

Where H is 1132 from A and M is (1132+x) from A (in the slope).

You'll get a quadratic equation including x

7. $335:1132$ as $\;590:1132 + x$

so

$\frac{{335}}
{{1132}} = \frac{{590}}
{{1132 + x}}$
. Now solve for $x$.

8. Originally Posted by Moo
Well, you can use Thalès theorem :

AC/AB=AH/AM

Where H is 1132 from A and M is (1132+x) from A (in the slope).

You'll get a quadratic equation including x
Thanks that was what I tought as the only way also, though the answer then is 861,67 and the correct answer should be 860... Very close but they don't say anything about going for the closest tenth (sorry for bad math english im from sweden).... I guess that the only way is doing that though to get the correct answer...

Thanks for the help there!

9. Originally Posted by liljeros
Thanks that was what I tought as the only way also, though the answer then is 861,67 and the correct answer should be 860... Very close but they don't say anything about going for the closest tenth (sorry for bad math english im from sweden).... I guess that the only way is doing that though to get the correct answer...

Thanks for the help there!
Yes, I find it too...