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Math Help - solving equation

  1. #1
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    solving equation

    Hi i have some problem solving this equation, I'm not sure its even possible but if it is it would give the answer to my task. so here it is:

    590^2+y^2=(1132+x)^2

    A fast answer here would be very much appreciated since I'm in a bit of a hurry

    Thank you in advance!

    Greetings from Rickard Liljeros

    OBs edit the "^2" in the end should be outside the ")"
    Last edited by liljeros; May 7th 2008 at 10:04 AM.
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  2. #2
    A riddle wrapped in an enigma
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    You can solve for x in terms of y or you can solve for y in terms of x, but you cannot come up with a unique value for x and y.
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  3. #3
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    Quote Originally Posted by liljeros View Post
    Hi i have some problem solving this equation, I'm not sure its even possible but if it is it would give the answer to my task. so here it is:

    590^2+y^2=(1132+x)^2

    A fast answer here would be very much appreciated since I'm in a bit of a hurry

    Thank you in advance!

    Greetings from Rickard Liljeros

    OBs edit the "^2" in the end should be outside the ")"
    y = \pm 3456, x = 2374, -4368
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  4. #4
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    Quote Originally Posted by Isomorphism View Post
    y = \pm 3456, x = 2374, -4368
    How can we know we're looking for integer solutions ?
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  5. #5
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    Quote Originally Posted by masters View Post
    You can solve for x in terms of y or you can solve for y in terms of x, but you cannot come up with a unique value for x and y.
    Thank you! Well then I must have done wrong when trying to solve my task. Maybe you could help me with how to think?

    It is about a skiing slope and i get some numbers but not all, The task is to get the length of one part of the slope, will make a picture that looks like the one in the paper:

    I should get X.

    m= meters (length)
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  6. #6
    Moo
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    Quote Originally Posted by liljeros View Post
    Thank you! Well then I must have done wrong when trying to solve my task. Maybe you could help me with how to think?

    It is about a skiing slope and i get some numbers but not all, The task is to get the length of one part of the slope, will make a picture that looks like the one in the paper:

    I should get X.

    m= meters (length)
    Well, you can use Thalès theorem :

    AC/AB=AH/AM

    Where H is 1132 from A and M is (1132+x) from A (in the slope).

    You'll get a quadratic equation including x
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  7. #7
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    335:1132 as \;590:1132 + x

    so

    \frac{{335}}<br />
{{1132}} = \frac{{590}}<br />
{{1132 + x}}. Now solve for x.
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  8. #8
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    Quote Originally Posted by Moo View Post
    Well, you can use Thalès theorem :

    AC/AB=AH/AM

    Where H is 1132 from A and M is (1132+x) from A (in the slope).

    You'll get a quadratic equation including x
    Thanks that was what I tought as the only way also, though the answer then is 861,67 and the correct answer should be 860... Very close but they don't say anything about going for the closest tenth (sorry for bad math english im from sweden).... I guess that the only way is doing that though to get the correct answer...

    Thanks for the help there!
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  9. #9
    Moo
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    Quote Originally Posted by liljeros View Post
    Thanks that was what I tought as the only way also, though the answer then is 861,67 and the correct answer should be 860... Very close but they don't say anything about going for the closest tenth (sorry for bad math english im from sweden).... I guess that the only way is doing that though to get the correct answer...

    Thanks for the help there!
    Yes, I find it too...
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