Originally Posted by
mcaelli Hi, I have an assignment due tomorrow. There are two questions that i am stuck on. Could you please help me out with them? They are:
1) (2a^³)^2 x 3(a^-4 b)^-³
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4b^-5
Hello! May I know if your question is:
(2a³)² x 3(a^-4)(b)-³
4b^-5
[it is b to the power of 3 right?]
If I solve this question:
(2a³)² x 3(a^-4)(b)-³
4b^-5
= 4(a^6) x 3b^5
4(a^4)(b³)
Cancelling off common terms 4 and a^4 and b^3, I will get: a² + b²
I think it is correct, but i am not sure of your question...