Solve the equation and express the answer in terms of .

This is what I am guessing:

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- May 6th 2008, 08:26 PMtheevilp0ptartsolve log equation
Solve the equation and express the answer in terms of .

This is what I am guessing:

- May 6th 2008, 08:42 PMblair_alane
- May 6th 2008, 08:48 PMo_O
NO!

"log" is not a variable. Just like you don't say "sin^2". It has to be the sin OF something. Similarly, you have to take the LOGARITHM of something.

Recall the definition:

The log operator takes the form of and allows you to solve for the exponent c if you have a and b. Look at the definition and see how it works here.

And as blair_alane said, where did the negative come from? - May 7th 2008, 05:16 AMtheevilp0ptart
So would it be this:

- May 7th 2008, 05:44 AMTangera
Hello! Yup, your answer is correct. :)