Use Descartes's Rule of Signs to determine the possible number of negative real zeros for the given function. So far I have this: 1 negative real root.
Last edited by theevilp0ptart; May 6th 2008 at 07:20 PM.
Follow Math Help Forum on Facebook and Google+
g(x) has -+-+ That's 3, so 3 or 1 positive. g(-x) has +--+ That's 2, so 2 or 0 negative. ALL the negative powers change sign for g(-x). You missed the term.
Last edited by TKHunny; November 22nd 2009 at 12:51 PM.
View Tag Cloud