Simplify the expression$\displaystyle log_{49}(7)$ How is the answer 1/2?
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Properties that will help you: $\displaystyle \log_{a} b = \frac{\log b}{\log a}$ Noting that $\displaystyle 49 = 7^{2}$, keep in mind that: $\displaystyle \log a^{b} = b\log a$
[Math]ln7/ln49/[/tex] = .5
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