Im not sure how to times through by 3/3 on the bottom

(2/3) / (1+(2/3)^2)^0.5

trying to get 2/(9+4x^2)^0.5 If somebody could show me how that'd be much appreciated

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- May 5th 2008, 04:03 AMi_zz_y_illreally easy cancel I can't do!
Im not sure how to times through by 3/3 on the bottom

(2/3) / (1+(2/3)^2)^0.5

trying to get 2/(9+4x^2)^0.5 If somebody could show me how that'd be much appreciated - May 5th 2008, 04:47 AMcolby2152
- May 5th 2008, 04:48 AMjanvdl