Im not sure how to times through by 3/3 on the bottom (2/3) / (1+(2/3)^2)^0.5 trying to get 2/(9+4x^2)^0.5 If somebody could show me how that'd be much appreciated
Follow Math Help Forum on Facebook and Google+
Originally Posted by i_zz_y_ill Im not sure how to times through by 3/3 on the bottom (2/3) / (1+(2/3)^2)^0.5 trying to get 2/(9+4x^2)^0.5 If somebody could show me how that'd be much appreciated What is squared? It is . Multiply that out through the "top" and "bottom" of the fraction.
Originally Posted by i_zz_y_ill Im not sure how to times through by 3/3 on the bottom (2/3) / (1+(2/3)^2)^0.5 trying to get 2/(9+4x^2)^0.5 If somebody could show me how that'd be much appreciated I'm sure you mean the following: Observe the in the numerator. We can move that 3 to the denominator of the entire function. Giving us: But we also know that: Thus: Simplify the denominator.
View Tag Cloud