Thread: really easy cancel I can't do!

Im not sure how to times through by 3/3 on the bottom

(2/3) / (1+(2/3)^2)^0.5

trying to get 2/(9+4x^2)^0.5 If somebody could show me how that'd be much appreciated

Originally Posted by i_zz_y_ill

Im not sure how to times through by 3/3 on the bottom

(2/3) / (1+(2/3)^2)^0.5

trying to get 2/(9+4x^2)^0.5 If somebody could show me how that'd be much appreciated

What is squared? It is .

Multiply that out through the "top" and "bottom" of the fraction.

Originally Posted by i_zz_y_ill

Im not sure how to times through by 3/3 on the bottom

(2/3) / (1+(2/3)^2)^0.5

trying to get 2/(9+4x^2)^0.5 If somebody could show me how that'd be much appreciated

I'm sure you mean the following:



Observe the in the numerator. We can move that 3 to the denominator of the entire function.

Giving us:




But we also know that:


Thus:


Simplify the denominator.