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Math Help - Solve by Substitution

  1. #1
    Mad
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    Solve by Substitution

    3x - 2y = 4
    x = 2

    3(2) - 2y = 4
    6 - 2y = 4
    2y = 2
    y = 1


    y = 2x - 1
    x + 2y = 3

    x + 2(2x - 1) = 3
    x + 4x - 2 = 3
    5x = 5
    x = 1
    y = 1


    Am I even doing this right? The book only gave two examples and that's not how it was done but I don't know what else to do. I missed this chapter because I picked the class up late and there aren't enough examples.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Mad View Post
    3x - 2y = 4
    x = 2

    3(2) - 2y = 4
    6 - 2y = 4
    2y = 2
    y = 1


    y = 2x - 1
    x + 2y = 3

    x + 2(2x - 1) = 3
    x + 4x - 2 = 3
    5x = 5
    x = 1
    y = 1


    Am I even doing this right? The book only gave two examples and that's not how it was done but I don't know what else to do. I missed this chapter because I picked the class up late and there aren't enough examples.
    Hello Mad ,

    Yes, those are correct
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  3. #3
    Mad
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    Oh, thank Goodness, I want to get this over with.
    Last edited by CaptainBlack; May 4th 2008 at 11:14 PM. Reason: removed refernce to diety
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