I've tried to factor this for a long time but I can't get it right.
(x-2y)^3 + 4(2y-x)
well the directions were for me to factor it completely. Since the problem was (x-2y)^3 + 4(2y - x). I figured I had to use one of those formulas. So at first I multiplied a -1 into (2y - x) to make it the same as the first part. Then it became (x - 2y)^3 + 4(2y - x). So I checked the answer, and it said the answer was:
(x - 2y)(x - 2y + 2)(x - 2y - 2)
So then I became confused... Like I don't see there's three -2y's and how the 2 and -2 from 4 went into the parenthesis.... yeah.. hehe