i need to add 5 square root (7) and 3 square root (28). i can't figure out how to do it. please help me!!!!!
First of all, the square root of 28= sq.root(7*4).....so it is also equal to 2 square root 7....so... 3 root 28 = 6 root 7.
so, 5 square root 7 + 6 square root 7 = 11 square root 7.
I dont know if my math is correct, but you just have to simplify your square roots.
Sorry for the sloppy math....
In general, you can break square roots apart - for example, $\displaystyle \sqrt{44} = \sqrt{4}\times\sqrt{11}$. Of course, the square root of 4 is 2, so you get $\displaystyle 2\sqrt{11}$.
When you look to break apart larger numbers under a square root sign, you want to try to break them up into two factors where one of the factors is a perfect square (4, 9, 16, ...).
yes! the first one I got right! here...I'll write it again...
$\displaystyle 28=\sqrt(7*4)$.....so it is also equal to $\displaystyle 2\sqrt7$....so...
$\displaystyle 3\sqrt28=3*2\sqrt7=6\sqrt7$
so, $\displaystyle 5\sqrt7+6\sqrt7=11\sqrt7$
is that somewhat less confusing? (i found out how to do latex! teehee) I probably just made it worse! sorry! I dont know how to lay it out....
hope that helps!
type [tex]\sqrt{Anything}[/tex] to get $\displaystyle \sqrt{Anything}$.
so it would look nicer if you had $\displaystyle \sqrt{7 * 4}$ or better yet $\displaystyle \sqrt{7 \cdot 4}$ ..........use \cdot to get the dot. so the last one we got by typing [tex]\sqrt{7 \cdot 4}[/tex]