# Thread: Systems of Equations with Substitution Method

1. ## Systems of Equations with Substitution Method

I have a test tomorrow and I can't figure out why I'm ending up with ridiculous numbers when doing this problem...

y + 3x = 7
2x + 3y = 14

Now I know that you're supposed to work with a variable with a coefficient of 1 because it helps you avoid fractions, so I figure it's best to solve for the "y" in "y + 3x = 7".

Here's what I'm doing...I'm trying to get the "y" by itself:

y + 3x = 7
-3x -3x
Is this right^? would it be y= 7 - 3x?

This is only the first step so I might need more help on this.

2. Originally Posted by endlesst0m
I have a test tomorrow and I can't figure out why I'm ending up with ridiculous numbers when doing this problem...

y + 3x = 7
2x + 3y = 14

Now I know that you're supposed to work with a variable with a coefficient of 1 because it helps you avoid fractions, so I figure it's best to solve for the "y" in "y + 3x = 7".

Here's what I'm doing...I'm trying to get the "y" by itself:

y + 3x = 7
-3x -3x
Is this right^? would it be y= 7 - 3x?

This is only the first step so I might need more help on this.
Yes, $\displaystyle y = 7 - 3x$ is correct. Using that method, you would then substitute into the second equation:

$\displaystyle 2x + 3(7 - 3x) = 14$

$\displaystyle 2x + 21 - 9x = 14$

$\displaystyle 2x - 9x = -7$

$\displaystyle -7x = -7$

$\displaystyle x = 1$