Can someone please help me expand this, (x-2)^(k+1). Thanks for the help
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Hi You can use the binomial theorem : $\displaystyle (a+b)^n=\sum_{i=0}^n\binom{n}{i}a^i\times b^{n-i}$
Originally Posted by cowboys111 Can someone please help me expand this, (x-2)^(k+1). Thanks for the help $\displaystyle (a + b)^{m} = \sum_{i = 0}^m {m \choose {m - i}}a^{m - i}b^i$ So $\displaystyle (x - 2)^{k+1} = \sum_{i = 0}^{k + 1} {{k + 1} \choose {k + 1 - i}}x^{k + 1 - i}(-2)^i$ -Dan
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