1. ## need help expanding

Thanks for the help

2. Hi

You can use the binomial theorem : $(a+b)^n=\sum_{i=0}^n\binom{n}{i}a^i\times b^{n-i}$

3. Originally Posted by cowboys111
Thanks for the help
$(a + b)^{m} = \sum_{i = 0}^m {m \choose {m - i}}a^{m - i}b^i$

So
$(x - 2)^{k+1} = \sum_{i = 0}^{k + 1} {{k + 1} \choose {k + 1 - i}}x^{k + 1 - i}(-2)^i$

-Dan