(a mod m) = (b mod m) Does this imply anything about a and b?

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Originally Posted by jzellt (a mod m) = (b mod m) Does this imply anything about a and b? They are in the same equivalence class and that $\displaystyle m|(a - b)$

Originally Posted by jzellt (a mod m) = (b mod m) Does this imply anything about a and b? Yes, it means that a and b leave the same remainder when divided by m.

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