The number of positive divisors of 105 is: a. 7 b. 8 c. 9 d. 10 e. 11
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Hello, So : 1-105 3-35 5-21 7-15 -> 8 You can also do this way : In general, the number of divisors of is ---> (1+1)(1+1)(1+1)=8
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