Hello, jscalalamoboy!
No clue ??
Okay, just this once . . . for you . . .
$\displaystyle \begin{Bmatrix}y \:\leq \:\frac{1}{5}x + \frac{12}{5} \\
y \:\geq \:x \\ y\:\geq\:x3 \end{Bmatrix}$
You need to graph the inequalities and shade the required region.
Graph the line: .$\displaystyle y \:=\:\frac{1}{5}x + \frac{12}{5}$
. . . It has yintercept $\displaystyle \frac{12}{5}$ and slope $\displaystyle \frac{1}{5}$
The inequality is $\displaystyle \leq$ . . . Shade the region below the line. Code:
 *;;
 *:::::;
 *::::::::
 *::::::::::
 *::::::::::::
*::::::::::::::
*:::::::::::::::
*:::::::::::::::::
 *::::::+::::      
::::::::::::::::::
::::::::::::::::

Graph the line: .$\displaystyle y \:=\:x$
. . It has y intercept 0 and slope 1.
The inequality is $\displaystyle \geq$ . . . Shade the region above the line. Code:
*::::::::::::::
*:::::::::::::
*::::::::::::
*:::::::::::
*::::::::::
*:::::::::
      *::::: 
 *::::::::
 *:::::::
 *::::::
 *

Graph the line: .$\displaystyle y \:=\:2x3$
. . It has yintercept 3 and slope 2.
The inequality is $\displaystyle \geq$ . . . Shade the region above the line. Code:
:::::::::::*
::::::::::*
::::::::::*
::::::::::*
::::::::::*
::::::::::*
   :::+:::*   
::::::::::*
::::::::::*
::::::::::*
::::::::::*
::::::::::
The solution is the triangular region common to all three.
And we are usually expected to find the coordinates of the vertices.
Code:

 o(3,3)
 *::*
 *:::::*
*::::::::*
(2,2)o::::::::::*
*:::::::*
        *:::*       
 *::*
 o(1,1)
