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Math Help - [SOLVED] Algebra (Cumulative Review) Linear Systems and Inequalities

  1. #1
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    [SOLVED] Algebra (Cumulative Review) Linear Systems and Inequalities

    Ok, I have no clue how to do these, its a linear inequality system.

    {y≤1/5x+12/5
    {y≥-x
    {y≥2x-3
    Btw, they are all in one bracket. How do I write equations?
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  2. #2
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    Hello, jscalalamoboy!

    No clue ??

    Okay, just this once . . . for you . . .


    \begin{Bmatrix}y \:\leq \:\frac{1}{5}x + \frac{12}{5} \\<br />
y \:\geq \:-x \\ y\:\geq\:x-3 \end{Bmatrix}

    You need to graph the inequalities and shade the required region.


    Graph the line: . y \:=\:\frac{1}{5}x + \frac{12}{5}
    . . . It has y-intercept \frac{12}{5} and slope \frac{1}{5}

    The inequality is \leq . . . Shade the region below the line.
    Code:
                    |                   *;;
                    |               *:::::;
                    |           *::::::::
                    |       *::::::::::
                    |   *::::::::::::
                    *::::::::::::::
                *:::|::::::::::::
            *:::::::|::::::::::
      - *:-:-:-:-:-:+:-:-:-:- - - - - - -
        ::::::::::::|::::::
        ::::::::::::|::::
                    |

    Graph the line: . y \:=\:-x
    . . It has y -intercept 0 and slope -1.

    The inequality is \geq . . . Shade the region above the line.
    Code:
        *:::::::::::|:::
          *:::::::::|::::
            *:::::::|:::::
              *:::::|::::::
                *:::|:::::::
                  *:|::::::::
        - - - - - - *:-:-:-:-:- -
                    | *::::::::
                    |   *:::::::
                    |     *::::::
                    |       *
                    |

    Graph the line: . y \:=\:2x-3
    . . It has y-intercept -3 and slope 2.

    The inequality is \geq . . . Shade the region above the line.
    Code:
                    |:::::::::::*
                    |::::::::::*
                   :|:::::::::*
                  ::|::::::::*
                 :::|:::::::*
                ::::|::::::*
        - - - -:-:-:+:-:-:* - - -
              ::::::|::::*
             :::::::|:::*
            ::::::::|::*
           :::::::::|:*
          ::::::::::|

    The solution is the triangular region common to all three.
    And we are usually expected to find the coordinates of the vertices.
    Code:
                    |
                    |           o(3,3)
                    |       *::*
                    |   *:::::*
                    *::::::::*
          (-2,2)o:::|:::::::*
                  *:|::::::*
    - - - - - - - - *:-:-:* - - - - - - -
                    | *::*
                    |   o(1,-1)
                    |
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  3. #3
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    how do you do those fun graphs soroban?
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  4. #4
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    YEAH! Thanks bro! I PASSED! WHOOOOOO!
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