Im stuck on this.

http://i137.photobucket.com/albums/q...tiger/ineq.jpg

I factorised it to (x-3)(x-2)

so there for

x = 3

x = 2

Im not sure how to find the values for which it is smaller/equal to 0.

Any suggestions?

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- April 28th 2008, 12:52 PMnugiboyInequality Help
Im stuck on this.

http://i137.photobucket.com/albums/q...tiger/ineq.jpg

I factorised it to (x-3)(x-2)

so there for

x = 3

x = 2

Im not sure how to find the values for which it is smaller/equal to 0.

Any suggestions? - April 28th 2008, 01:01 PMhousefire
Now you know where it crosses the x-axis, if you draw a quick sketch of the graph, you'll be able to see easily where the values you want lie.

- April 28th 2008, 01:02 PMo_O
Pick numbers in the intervals and test them to see if any of them satisfies your inequality. The one that does is representative of all the numbers on that interval.

Code:

<---------|---------|--------->

2 3

- April 28th 2008, 01:05 PMnugiboy
- April 28th 2008, 01:06 PMMoo
Hello,

If you have two numbers a and b, the product ab is negative if and only if a and b are of different signs.

This means that if a<0, b>0 and if a>0, b<0 :) - April 28th 2008, 03:40 PMKrizalid

hence